9/48; 10/48; 11/48; 12/48; 13/48; 14/48; 15/48
\(\frac{1}{6}=\frac{8}{48}\)
\(\frac{1}{3}=\frac{12}{48}\)
Vậy \(\frac{8}{48}< \frac{9}{48};\frac{10}{48};\frac{11}{48}< \frac{12}{48}\)
Vậy a bằng 9;10;11
\(\frac{1}{6}< \frac{a}{48}< \frac{1}{3}\)
\(=\frac{8}{48}< \frac{a}{48}< \frac{16}{48}\)
\(=\frac{a}{48}=\frac{9}{48};\frac{10}{48};\frac{11}{48};\frac{12}{48};\frac{13}{48};\frac{14}{48};\frac{15}{48}\)