Ta có: \(\left(x-1\right)\left(x-2\right)\left(x-3\right)+\left(x+1\right)\left(x+2\right)\left(x+3\right)-2x^3=41\)
\(\Leftrightarrow\left(x^2-3x+2\right)\left(x-3\right)+\left(x^2+3x+2\right)\left(x+3\right)-2x^3=41\)
\(\Leftrightarrow x^3-6x^2+11x-6+x^3+6x^2+11x+6-2x^3=41\)
\(\Leftrightarrow22x=41\)
\(\Rightarrow x=\frac{41}{22}\)