a)\(\frac{3n+7}{n-2}=\frac{3n-6+13}{n-2}=3+\frac{13}{n-2}\)
để 3n+7/n-2 thuộc Z thì \(n-2\in\left\{-13;-1;1;13\right\}\Rightarrow n\in\left\{-12;1;3;15\right\}\)
b)\(\frac{n+8}{n-2}=\frac{n-2+10}{n-2}=1+\frac{10}{n-2}\)
để n+8/n-2 thuộc N thì \(n-2\in\left\{-10;-5;-2;-1;1;2;5;10\right\}\)
\(ncóthể\in\left\{-8;-3;0;1;3;4;7;12\right\}\)mà n thuộc N
\(n\left\{0;1;3;4;7;12\right\}\)