\(\frac{n-2}{n+2}-\frac{n-1}{n+2}+\frac{-4}{n+2}=\frac{n-2-n-1+\left(-4\right)}{n+2}=\frac{\left(n-n\right)-2-1+\left(-4\right)}{n+2}=\frac{-7}{n+2}\)
\(\Rightarrow n+2\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\)
\(n+2\) | \(-7\) | \(-1\) | \(+1\) | \(+7\) |
\(n\) | \(-9\) | \(-3\) | \(-1\) | \(5\) |