n+11 chia het n+1
n+11=(n+1)+10
=> \(\frac{n+11}{n+1}=1+\frac{10}{\left(n+1\right)}\)
vay n+1 phai la uoc cua 10
U(10)=(1,2,5,10)
n=(0,1,4,9)
c)
\(\frac{7n}{n-3}=\frac{7.\left(n-3\right)+21}{n-3}=7+\frac{21}{\left(n-3\right)}\)
vay: n-3 phai la uoc cua (21)
U(21=1,3,7,21)
n=(4,6,10,24)
f)
\(\frac{\left(4n+3\right)}{3n+1}=\frac{\left(3n+1\right)+\left(n+2\right)}{3n+1}=1+\frac{\left(n+2\right)}{3n+1}\)
n+2 chia het cho 3n+1
n phai nho hon 2
n=1 =\(\frac{\left(n+2\right)}{3n+1}=\frac{3}{4}+>\left(\right)loai\)
n=0=
nhan
ds: n=0