n = 5 vì :
=> 3.5 + 1 : 5 - 3
= 15 + 1 : 5 - 3
= 16 : 2
= 8
=> n = 5 vì 3.5 + 1 CHC 5 - 3 .
\(\frac{3n+1}{n-3}=\frac{3n-9+10}{n-3}=\frac{3.\left(n-3\right)+10}{n-3}=\frac{3.\left(n-3\right)}{n-3}+\frac{10}{n-3}=3+\frac{10}{n-3}\)
Mà 3 \(\in N\Rightarrow n-3\inƯ\left(10\right)\)
\(\Rightarrow n-3\in\left\{1;2;5;10\right\}\Rightarrow n\in\left\{4;5;8;13\right\}\)