\(B=x^2-5x+3\)
\(=\left(x^2-2.\frac{5}{2}x+\frac{25}{4}\right)-\frac{25}{4}+3\)
\(=\left(x-\frac{5}{2}\right)-\frac{13}{4}\)
Vậy \(B_{min}=-\frac{13}{4}\)
\(B=x^2-5x+3\)
\(=\left(x^2-2.\frac{5}{2}x+\frac{25}{4}\right)-\frac{25}{4}+3\)
\(=\left(x-\frac{5}{2}\right)-\frac{13}{4}\)
Vậy \(B_{min}=-\frac{13}{4}\)
1)Tim MAX cua A= (6x^2-2x+1)/ x^2
2)tim MIN va MAX C= (3-4x)/(X^2+1)
3) Tim MIN va MAX P = x^2+y^2
biet giua x va y co moi quan he nhu sau : 5x^2+8xy+5y^2=36
4)tim MAX Q = -x^2-y^2+xy+2x+2y
tim min k=5x^2+4y^2-4xy+4y+2x+3
cho 5x+12y=13 tim min x2+y2
Tim min , maz của Q =\(\frac{x}{x^2-5x+7}\)
5x ^2 +4y^2 - 4xy + 4y +2x +3
Tim Min
tim Min cua bieu thuc
a) A = x2 + xy + y2 - 3x - 3y
b) B = -5x2 - 2xy - 2y2 + 14x + 10y -1
1. Tìm Min
a, 3x^2 + 5x
b, (2x-1)^2 - x^2
2.Cho x+y=2. Tìm Min A = x^2+y^2
3. tìm Min A = x^2 + 6y^2 + 4xy - 2x - 8y + 2016
choP=(1/(x-2)-x^2/(8-x^3)*(x^2+2x+4)/(x+2)0/1/(x^2-4) tim DKXD va rut gon b tim Min p c tim x nguyen de p chia het cho x^2+1
Tìm min
F=3x^2 +x -2
G= 4x^2+2x-1
H=5x^2-x+1
Tìm max
A= -x^2 -6x+3
B=-x^2+8x-1
C= -x^2-3X+4
D= -2x^2+3x-1
E= -3x^2 – x +2
F= -5x^2 -4x +3
G= -3x^2 – 5x+1