B = 5 - 2z2
Vì 2z2 ≥ 0 => B = 5 - 2z2 ≤ 5
Dấu "=" xảy ra khi 2z2 = 0 => z = 0
Vậy Bmax là 5 tại z = 0
C = |x - 3| + |5 - x| ≥ |x - 3 + 5 - x| = 2
Dấu "=" xảy ra khi (x - 3)(5 - x) ≥ 0 <=> 5 ≥ x ≥ 3
Vậy Cmin = 2 tại 5 ≥ x ≥ 3
Tim GTNN hoac GTLN cua cac bieu thuc sau :
a) A = 3|2x - 1| - 5 b) B = 10 - 5 |x - 2| c) C =\(\frac{1}{\left|x-2\right|+3}\)
B = | 3x - 1 | - 5
C = 2/(x + 3 )^2+3
tim gia tri nho nhat hoac lon nhat cua cac bieu thuc sau
a)A=\(|x-4|-5\)
b)B=\(-|x+3|+7\)
tim gia tri lon nhat hoac nho nhat cua cac bieu thuc sau
c)C= \(3+|x-2|\)
d)D=\(5-|2x-1|\)
tim GTLN cua bieu thuc A=100-/x+5/
Tim gia tri lon nhat hoac nho nhat cua cac bieu thuc sau
a, C=(x-1)2+\(|2y+2|\)-3
Tim gia tri nho nhat hoac gia tri lon nhat cua bieu thuc D = (x + 5)^2 + (2y - 6)^2 + 1
Tim GTNN cua cac bieu thuc:
a,A=|x-1|+|x-2|+|x-3|+|x-4|+...+|x-10|
b,P=|3x-6|+|y2+1|+2015
Cach lam nua nhe
Lam nhanh minh se tick
Tim GTNN cua cac bieu thuc:
a,A=|x-1|+|x-2|+|x-3|+|x-4|+...+|x-10|
b,P=|3x-6|+|y2+1|+2015
Cach lam nua nhe
Lam nhanh minh se tick
