\(-2x^2-16x+34=-2\left(x^2+8x+16\right)+66=-2\left(x+4\right)^2+66\le66\)
Dấu "=" xảy ra khi \(-2\left(x+4\right)^2=0\Rightarrow x=-4\)
A = -2x2 - 16x + 34 = -2(x2 + 8x - 17) = -2 [ (x + 4)2 - 33 ] = -2(x + 4)2 + 66 \(\le\)66 (vì -2(x+4)2 \(\le\)0)
Max A = 66 \(\Leftrightarrow\)x + 4 = 0 \(\Leftrightarrow\)x = -4