Question

Tìm giá trị x, y thỏa mãn: \(^{\left|2x-27\right|^{2011}+\left(3y+10\right)^{2012}=0}\)

Answer 1

Vì \(\left|2x-27\right|\ge0\Rightarrow\left|2x-27\right|^{2011}\ge0\);  \(\left(3y+10\right)^{2012}\ge0\)

=>\(\left|2x-27\right|^{2011}+\left(3y+10\right)^{2012}\ge0\)

Dấu "=" xảy ra khi \(\left|2x-27\right|^{2011}=\left(3y+10\right)^{2012}=0\Leftrightarrow\hept{\begin{cases}\left|2x-27\right|=0\\\left(3y+10\right)^{2012}=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}2x-27=0\\3y+10=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=\frac{27}{2}\\y=-\frac{10}{3}\end{cases}}\)