a) \(\left(x+1\right)^2+3\ge0+3=3\)
Dấu \(=\)xảy ra khi \(x+1=0\Leftrightarrow x=-1\).
b) \(\left|x-1\right|+y^2-10\ge0+0-10=-10\)
Dấu \(=\)xảy ra khi \(\hept{\begin{cases}x-1=0\\y=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1\\y=0\end{cases}}\).