Ta có : B = x2 - 3x + 5
=> B = \(x^2-2.x.\frac{3}{2}+\frac{9}{4}+\frac{11}{4} \)
=> B = \(\left(x-\frac{3}{2}\right)^2+\frac{11}{4}\)
Mà : \(\left(x-\frac{3}{2}\right)^2\ge0\forall x\)
=> B = \(\left(x-\frac{3}{2}\right)^2+\frac{11}{4}\)\(\ge\frac{11}{4}\forall x\)
Vậy Bmin = \(\frac{11}{4}\), dấu "=" sảy ra khi và chỉ khi x = \(\frac{3}{2}\)