Vì \(\left(2x+2015\right)\ge0\)vời mọi x
Nên \(\left(2x+2015\right)-3\ge-3\)với mọi x
Min \(\left(2x+2015\right)-3=3\Leftrightarrow2x+2015=0\)\(\Leftrightarrow2x=-2015\)\(\Leftrightarrow x=\frac{-2015}{2}\)
Vậy Min \(\left(2x+2015\right)-3=3\Leftrightarrow x=\frac{-2015}{2}\)