\(D=\frac{x^2+8}{x^2+3}=\frac{x^2+3+5}{x^2+3}=1+\frac{5}{x^2+3}\)
ta có x^2+3>=3 => 5/(x^2+3)<=5/3
=> D = 8/3 tại x=0
câu b)
2(x-1)2 +3 >=3
=> C <= 1/3 tại x=1
gia tri lon nhat cua bieu thuc
\(C=\frac{3}{|x-1|x+\left(x-1\right)^4+1}\frac{1}{2}\)
TIM GIA TRI LON NHAT CUA BIEU THUC :
C=2+12/3x/X+5/+4
TIM GIA TRI NHO NHAT CUA BIEU THUC
C= -15/ 4x / 3X+7/+3
tim gia tri lon nhat cua bieu thuc B=x^2+y^2+3/x^2+y^2+2
tim gia tri nho nhat hoac lon nhat cua bieu thuc sau:
x^2+15/x^2+3
gia tri lon nhat cua bieu thuc C=3/|x-1|+(x-1)^4+1 + 1/2
Tim gia tri lon nhat cua bieu thuc P = -2|x-1|-7
1. so x>0 thoa man \(\frac{5}{x}=\frac{x+1}{22}\)
2. GTLN cua x thoa man \(5^{\left(x-2\right)\left(x+3\right)}\)
3. Gia tri x<0 thoa man /\(x^2+50\)/=/\(-2x^2\)-1/
4. Gia tri nguyen cua x thoa man \(\left(3x-4\right)^5\)=\(^{\left(3x-4\right)^7}\)la x=
5. So gia tri cua x thoa man /x-2014/+/x-2015/=0
6. Gia tri cua x de bieu thuc A=\(\frac{x-3+5}{3-x+2}\)dat gia tri lon nhat la x=
tim gia tri nguyen cua x de cac bieu thuc sau co gia tri lon nhat tim gia tri do\
A=\(\frac{1}{7-X}\)
B=\(\frac{27-2X}{12-X}\)
C=\(\frac{14-X}{4-X}\)
D=\(\frac{7X-8}{2X-3}\)
tim cac gia tri nguyen cua x de cac bieu thuc sau co gia tri lon nhat tim gia tri do
\(A=\frac{1}{7-x}\)
\(B=\frac{27-2x}{12-x}\)
C=\(\frac{14-x}{4-x}\)
D=\(\frac{7x-8}{2x-3}\)
