\(\frac{x-y}{x+2y}=\frac{3}{4}\)
\(\Leftrightarrow\left(x-y\right).4=\left(x+2y\right).3\)
\(\Leftrightarrow4x-4y=3x+6y\)
\(\Leftrightarrow4x-3x=6y+4y\)
\(\Leftrightarrow x=10y\)
Thay x=10y vào \(\frac{x}{y}\)ta được :
\(\frac{10y}{y}=10\)
Vậy \(\frac{x}{y}=10\)
\(\frac{\times-y}{\times+2y}=\frac{3}{4}\)
\(\Rightarrow\frac{\left(\times+2y\right)-3y}{\times+2y}=\frac{3}{4}\)
\(\Rightarrow1-\frac{3y}{\times+2y}=\frac{3}{4}\)
\(\Rightarrow\frac{3y}{\times+2y}=\frac{1}{4}\)
\(\Rightarrow12y=\times+2y\)
\(\Rightarrow\times=10y\)
\(\Rightarrow\frac{\times}{y}=10\)
mình thấy 10 đâu có bằng \(\frac{3}{4}\) đâu bạn
