Question

tìm đa thức A biết :

a, A + ( x^2 + y^2 ) = 5^2 + 3^2 - xy

b, ( 1/2 xy^2 + x^2 - x^2y )  - A = - xy^2 + xy^2 + 2 

Ai nhanh mik tik cho !!

Answer 1

a/ \(A+\left(x^2+y^2\right)=5^2+3^2-xy\)

=> \(A+\left(x^2+y^2\right)=25+9-xy\)

=> \(A+\left(x^2+y^2\right)=36-xy\)

=> \(A=\left(36-xy\right)-\left(x^2+y^2\right)\)

=> \(A=36-xy-x^2-y^2\)

b/ \(\left(\frac{1}{2}xy^2+x^2-x^2y\right)-A=-xy^2+xy^2+2\)

=> \(\left(\frac{1}{2}xy^2+x^2-x^2y\right)-A=2\)

=> \(-A=2-\left(\frac{1}{2}xy^2+x^2-x^2y\right)\)

=> \(-A=2-\frac{1}{2}xy^2+x^2-x^2y\)

=> \(-A=-\left(-2+\frac{1}{2}xy^2-x^2+x^2y\right)\)

=> \(A=-2+\frac{1}{2}xy^2-x^2+x^2y\)