\(\left(2x+1\right)\left(y-5\right)=12\)
\(\Rightarrow2x+1;y-5\inƯ\left(12\right)\)
\(Ư\left(12\right)=\left\{1;2;3;4;6;12\right\}\)
Ta có bảng sau
2x+1 | 1 | 2 | 3 | 4 | 6 | 12 |
y-5 | 12 | 6 | 4 | 3 | 2 | 1 |
x | 0 | / | 1 | / | / | / |
y | 17 | / | 9 | / | / | / |
vậy \(\hept{\begin{cases}x=0\\y=17\end{cases}}\) hoặc \(\hept{\begin{cases}x=1\\y=9\end{cases}}\)