Question

Tìm các số nguyên x,y,z,t

\(\frac{x}{24}=\frac{y}{-18}=-\frac{28}{z}=\frac{-10}{t}=\frac{-2}{3}\)

Answer 1

\(\frac{x}{24}=\frac{-2}{3}\Leftrightarrow x=\frac{-2\times24}{3}=-16\)

\(\frac{y}{-18}=\frac{-2}{3}\Leftrightarrow y=\frac{-2\times-18}{3}=12\)

\(\frac{-28}{z}=\frac{-2}{3}\Leftrightarrow z=\frac{-28\times3}{-2}=42\)

\(\frac{-10}{t}=\frac{-2}{3}\Leftrightarrow t=\frac{-10\times3}{-2}=15\)

Answer 2

\(\frac{x}{24}=\frac{y}{-18}=\frac{-28}{z}=\frac{-10}{t}=\frac{-2}{3}\)

\(\Rightarrow t=-15\)

\(\Rightarrow z=42\)

\(\Rightarrow y=12\)

\(\Rightarrow x=-16\)

Answer 3

Ta có \(\frac{x}{24}=\frac{-2}{3}\)

\(\Rightarrow3x=-48\)

\(\Rightarrow x=-16\)

\(\frac{y}{-18}=\frac{-2}{3}\)

\(\Rightarrow3y=36\)

\(\Rightarrow y=12\)

\(\frac{-28}{z}=\frac{-2}{3}\)

\(\Rightarrow-2z=-84\)

\(z=42\)

\(\frac{-10}{t}=\frac{-2}{3}\)

\(\Rightarrow-2t=-30\)

\(\Rightarrow t=15\)