Ta có:
`x^2+x-y^2=0`
`<=> 4x^2+4x-4y^2=0`
`<=> (2x+1)^2 - (2y)^2 = 1`
`<=> (2x+2y+1)(2x-2y+1)=1 (*)`
Vì `x,y` nguyên nên từ (*) ta có:
TH1:
`2x+2y+1=1` `<=> `x=0`
`2x-2y+1=1` `<=>` `y=0`
TH2:
`2x+2y+1=-1` `<=> x-1`
`2x-2y+1=-1` `<=> 0`
Vậy `(x;)= {(0;0, (-1;0)}`