Question

Tìm  các số nguyên x;y thỏa mãn: \(\frac{x}{8}\)=\(\frac{y}{12}\)và 2x+3y=-156

Answer 1

\(\frac{x}{8}=\frac{y}{12}=\frac{2x+3y}{16+36}=\frac{-156}{52}=-3\)

x=-3.8=-24

y=-3.12=-36

Answer 2

Ta có : \(\frac{x}{8}=\frac{y}{12}=\frac{2x}{16}=\frac{3y}{36}=\frac{2x+3y}{16+36}=\frac{-156}{52}=-3\)

=> x = -3.8 = -24 ; y = -3.12 = -36