Theo tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x}{6}=\frac{y}{11}=\frac{3x}{18}=\frac{2y}{22}=\frac{3x-2y}{18-22}=\frac{-20}{-4}=5\)
\(\Rightarrow x=30;y=55\)
Vậy x = 30 ; y = 55
Theo tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x}{6}=\frac{y}{11}=\frac{3x}{18}=\frac{2y}{22}=\frac{3x-2y}{18-22}=\frac{-20}{-4}=5\)
\(\Rightarrow x=30;y=55\)
Vậy x = 30 ; y = 55
tim cac so nguyen x , y biet
e) (x - 3) (x + y)=-11
f)xy + 3x - 2y - 6 = 5
Tim cac so nguyen x,y biet
a) \(\frac{x}{4}=\frac{y}{7}\)va \(x-y=9\)
b) \(\frac{x}{2}=\frac{y}{5}\)va 3x - y =5
Tim cac so nguyen x,y biet
\(\frac{x}{4}=\frac{y}{7}va-y=9\)
Tim cac so nguyen x , y biet x . y =30 va x+y=-11
Tim cac so nguyen x,y biet
\(\frac{x-3}{y-2}=\frac{3}{2}\) va x - y = 4
Tim cac so nguyen x,y biet
\(\frac{x+3}{y-1}\) =\(\frac{3}{4}\)va x + y = 5
Tim cac so nguyen duong x;y biet: |x-2y+1|.|x+4y+3|=20
tim cac so nguyen duong x;y biet |x-2y +1|.|x+4y+3| =20
Tim cac so nguyen duong x,y biet |x-2y+1|.|x+4y+3| = 20