Tim cac so nguyen duong x;y;z thoa man x!+y!=10.z+9
tìm x thỏa mãn : 2005=|x-4|+|x-10|+|x+101|+|x+990|+|x+1000|
tìm x thỏa mãn : 2005=|x-4|+|x-10|+|x+101|+|x+990|+|x+1000|
Tìm x nguyên để |x-4|+|x-10|+|x+101|+|x+990|+|x+1000|=2005
tìm x thỏa mãn 2005=|x-4|+|x-10|+|x+101|+|x+990|+|x+1000|
tìm x thỏa mãn 2005=|x-4|+|x-10|+|x+101|+|x+990|+|x+1000|
tìm x thỏa mãn 2005=|x-4|+|x-10|+|x+101|+|x+990|+|x+1000|
c1: Tap hop cac gia tri nguyen cua x thoa man \(\left(x+\frac{5}{4}\right)\left(x-\frac{19}{7}\right)\)<0
c2: Neu x,y la cac so nguyen thoa man 2xy+4y=6 thi y co the nhan nhung gia tri nam trong tap hop nao
c3: tim 3 so x,y,z biet x+y=8,x+z=10,y+z=12
C4: Gia tri cua x thoa man (x+3)^2=25 va x^3>0 la x=
Tim tat ca cac so nguyen x thoa man: (x+2014)^2=64.(x+2007)^3