Question

tim cac so nguyen x biet

a)\(\frac{x-1}{9}\)=\(\frac{8}{3}\)

b)\(\frac{x+2}{3}\)=\(\frac{2x-1}{5}\)

Answer 1

a, \(\frac{x-1}{9}=\frac{8}{3}\Leftrightarrow\frac{x-1}{9}=\frac{24}{9}\Leftrightarrow x-1=24\Leftrightarrow x=25\)

b, \(\frac{x+2}{3}=\frac{2x-1}{5}\Leftrightarrow\frac{5x+10}{15}=\frac{6x-3}{15}\Leftrightarrow5x+10=6x-3\)

\(\Leftrightarrow5x+10-6x+3=0\Leftrightarrow-x+13=0\Leftrightarrow x=13\)

Answer 2

a) \(\frac{x-1}{9}=\frac{8}{3}\)

\(\Leftrightarrow3\left(x-1\right)=8.9\)

\(\Leftrightarrow3x-3=72\)

\(\Leftrightarrow3x=75\)

\(\Leftrightarrow x=25\)

b) \(\frac{x+2}{3}=\frac{2x-1}{5}\)

\(\Leftrightarrow5\left(x+2\right)=3\left(2x-1\right)\)

\(\Leftrightarrow5x+10=6x-3\)

\(\Leftrightarrow5x-6x=-3-10\)

\(\Leftrightarrow-x=-13\)

\(\Leftrightarrow x=13\)