Vì |x-3|>/=0
=>|x-3|+1>/=0+1
=> A>/=1
dấu "=" xảy ra khi<=>|x-3|=0
x-3=0
x=0+3
x=3
Vậy min A=1
Khi x=3
A = | x - 3 | + 1
Vì | x - 3 | \(\ge0\forall x\)
=> | x - 3 | + 1 \(\ge1\forall x\)
=> A \(\ge1\forall x\)
=> A = 1 <=> | x - 3 | = 0
<=> x - 3 = 0
<=> x = 3
Vậy A min = 1 khi x = 3