Ta có: \(2^{5x}:2^{4x}=32\)
\(\Rightarrow5x-4x=32\)
\(\Rightarrow x=32\)
Vậy \(x=32.\)
Ta có \(2^{5x}+2^{4x}=32\)
\(\Rightarrow2^{5x-4x}=32\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
Vậy \(x=32\)
Này
Có \(2^{5x}:2^{4x}=32\)
\(\Rightarrow2^{5x-4x}=2^5\)
\(\Rightarrow2^x=2^5\)
Vậy \(x=5\)
Xl, cho mk sửa lại ạ!
Ta có: \(2^{5x}:2^{4x}=32\)
\(\Rightarrow2^{5x-4x}=32\)
\(\Rightarrow2^{5x-4x}=2^5\)
\(\Rightarrow5x-4x=5\)
\(\Rightarrow x=5\)
Vậy \(x=5.\)