Question

Tìm x biết 

2x + 2 {-[-x-3(x-3)]} = 2

Answer 1

Ta có: \(2x+2\left\{-\left[-x-3\left(x-3\right)\right]\right\}=2\)

\(\Leftrightarrow2x+2\left\{-\left[-x-3x+9\right]\right\}=2\)

\(\Leftrightarrow2x+2\left\{x+3x-9\right\}=2\)

\(\Leftrightarrow2x+8x-18=2\)

\(\Leftrightarrow10x=20\)

hay x=2

Vậy: x=2

Answer 2

\(2x+2\left\{-\left[-x-3.\left(x-3\right)\right]\right\}=2\)

\(\Leftrightarrow2x+2\left[-\left(-x-3x+9\right)\right]=2\)

\(\Leftrightarrow2x+2\left(x+3x-9\right)=2\)

\(\Leftrightarrow2x+2x+6x-18=2\)

\(\Leftrightarrow10x=2+18\)

\(\Leftrightarrow10x=20\)

\(\Leftrightarrow x=20:10\)

\(\Leftrightarrow x=2\)

\(\text{Vậy }x=2\)