a)
Ta có:
10 = 2.5
12 = 22.3
15 = 3.5
BCNN(10;12;15) = 22.5.3 = 60
b)
8 = 23
9 = 32
11 = 11
BCNN(8;9;22) = 23.32.11 = 792
c)
24 = 23.3
40 = 23.5
168 = 23.3.7
BCNN(24;40;168) = 23.3.5.7 = 840
a, 10=2.5
12=22.3
15=3.5
=>BCNN(10;12;15)=22.3.5=60
b, 8=23
9=32
11=11.1
=> BCNN(8;9;11)=23.32.11=792