wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww
Ta có :
\(bc=6\)\(\Rightarrow\)\(c=\frac{6}{b}\)\(\left(1\right)\)
\(ac=3\)\(\Rightarrow\)\(c=\frac{3}{a}\)\(\left(2\right)\)
Từ (1) và (2) suy ra \(\frac{3}{a}=\frac{6}{b}\)\(\Leftrightarrow\)\(\frac{1}{a}=\frac{2}{b}\)
\(\Leftrightarrow\)\(\frac{1}{a}.\frac{2}{b}=\frac{2}{b}.\frac{2}{b}\)
\(\Leftrightarrow\)\(\frac{2}{ab}=\frac{4}{b^2}\)
\(\Leftrightarrow\)\(\frac{2}{z}=\frac{4}{b^2}\)
\(\Leftrightarrow\)\(2b^2=4z\)
\(\Leftrightarrow\)\(b^2=2z\)
\(\Leftrightarrow\)\(b=\sqrt{2z}\)
\(\Rightarrow\)\(bc=6\)\(\Leftrightarrow\)\(c=\frac{6}{b}=\frac{6}{\sqrt{2z}}\)
\(\Rightarrow\)\(ac=3\)\(\Leftrightarrow\)\(a=3:\frac{6}{\sqrt{2z}}=\frac{3\sqrt{2z}}{6}=\frac{\sqrt{2z}}{2}\)
Vậy \(a=\frac{\sqrt{2z}}{2}\)\(;\)\(b=\sqrt{2z}\) và \(\frac{6}{\sqrt{2z}}\)
