vì b12{12;24;36;...}
vì x phụ thuộc vào 24 < x < 48 => x=36
B(12)= {0 ; 12 ; 24 ; 36; 48 ; ...}
24 < a < 48 => a= 36
B (12) = { 0;12;24;36;48;...}
mà 24 < x < 48 nên x = 36
vì b12{12;24;36;...}
vì x phụ thuộc vào 24 < x < 48 => x=36
B(12)= {0 ; 12 ; 24 ; 36; 48 ; ...}
24 < a < 48 => a= 36
B (12) = { 0;12;24;36;48;...}
mà 24 < x < 48 nên x = 36
tim x dua vao quan he uoc boi:
tim so tu nhien x sao cho x-1 la uoc cua 12
tim so tu nhien x sao cho 2x+1 la uoc cua 28
tim so tu nhien x sao cho x+15 la boi cua x+3
tim cac so nguyen x,y sao cho (x+1)(y-2)=3
tim so nguyen x sao cho(x+2).(y-1)=2
tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180
tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5
tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8
tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150
tim so x nho nhat khac 0b biet x chia het cho 24 va 30
40 chia het cho x . 56 chia het cho x va x>6
a) 2345-1000:[19-2(21-18)mu 2]
b)107-{38+[7.3 mu 2-24:6+(9-7) mu 3]} :15
c) 10- [(2 mu 2-48).5+(2 mu 3 .10+8)]:28
2) tim so tu nhien a,biet rang a gan den 1000,a:12,a:21 deu co du la 5
3) tim boi chung lon hon 5000 be hon 10000 cua cac so 126;140;180.
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
ket qua cua phep tinh -36-12 la
A.-24 B.48 C.24 D.-48
tim hai so khi biet thuong cua chung la 5 va hieu cua chung la 48
Tim 2 so tu nhien biet tich cua chung la 8+48 va ucln cua chung la 27
tìm a va b biet hieu cua chung bang 48 va ƯCLN = 12
tim ucln cua 12 vs 18
12 vs 10
24 vs 48
300 vs 280
9 vs 81
trinh bay cach giai gium minh voi
TIM X THUOC N, BIET
a,12 CHIA HET 2X +1
b, 24 chia het 2X -1