Question

Tim a,b\(\in Z\)biết

\(\frac{1}{a}=\frac{1}{6}+\frac{b}{3}\)\(\frac{a}{4}-\frac{1}{b}=\frac{3}{4}\)

 

Answer 1

1.\(\frac{1}{a}=\frac{1}{6}+\frac{b}{3}=\frac{1}{6}+\frac{2b}{6}=2b+\frac{1}{6}=\frac{1}{a}\Rightarrow(2b+1)\cdot a=6=2b\cdot a+a=6=3a\cdot b=6\)

\(a\cdot b=\frac{6}{a}\)

\(3\cdot2\cdot b=6\Rightarrow a=2;b=1\)

2. \(\frac{a}{4}-\frac{1}{b}=\frac{3}{4}\)hay \(\frac{a}{4}-\frac{3}{4}=\frac{1}{b}=a-\frac{3}{4}=\frac{1}{b}=>(a-3)\cdot6=4\)

\(6a-18=4\)

\(6a=4+18=22\)

\(=>A\in\varnothing\)

Đúng nhé bạn