Ta có 2abc x 3 = abc1
=> (2000 + abc) x 3 = abc x 10 + 1
=> 6000 + abc x 3 = abc x 10 + 1
=> abc x 7 = 5999
=> abc = 5999 : 7
=>abc = 857
Ta có 2abc x 3 = abc1
=> (2000 + abc) x 3 = abc x 10 + 1
=> 6000 + abc x 3 = abc x 10 + 1
=> abc x 7 = 5999
=> abc = 5999 : 7
=> abc = 857
Vậy abc = 857.