\(2a=3b;5b=7c\Rightarrow\frac{a}{3}=\frac{b}{2};\frac{b}{7}=\frac{c}{5}\Rightarrow\frac{a}{21}=\frac{b}{14};\frac{b}{14}=\frac{c}{10}\)
\(\Rightarrow\frac{a}{21}=\frac{b}{14}=\frac{c}{10}\)
áp dụng tính chất của dãy tỉ số băng nhau bằng nhau ta có:
\(\frac{a}{21}=\frac{b}{14}=\frac{c}{10}=\frac{3a+5c-7b}{3.21+5.10-7.14}=\frac{30}{15}=2\)
suy ra: \(\frac{a}{21}=2\Rightarrow a=2.21=42\)
\(\frac{b}{14}=2\Rightarrow b=2.14=28\)
\(\frac{c}{10}=2\Rightarrow c=2.10=20\)
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Chuc ban hoc dot
Cho tam giác ABC cường ở a trên toàn AC lấy điểm Dsao cho AD=AC Chứng minh tam giác ABC= tam giác ABD