\(\frac{a}{b}\)=\(\frac{7}{8}\) \(\Rightarrow\) a = 7k, b = 8k voi k \(\in\) N*
UCLN(a,b)=12
\(\Rightarrow\) UCLN(7k,8k)=12
ma 7,8 la 2 so nguen to cung nhau nen k=12
vay a=12*7=84
b=12*8=96
vay \(\frac{a}{b}\) =\(\frac{84}{96}\)
\(\frac{a}{b}\)=\(\frac{7}{8}\) \(\Rightarrow\) a = 7k, b = 8k voi k \(\in\) N*
UCLN(a,b)=12
\(\Rightarrow\) UCLN(7k,8k)=12
ma 7,8 la 2 so nguen to cung nhau nen k=12
vay a=12*7=84
b=12*8=96
vay \(\frac{a}{b}\) =\(\frac{84}{96}\)
Tim 2 so a va b biet UCLN(a,b)=12;BCNN(a,b)=72
1,tim 2 so tu nhien biet tong chung = 66 UCLN=6 co 1 so chia het cho 5
2,tim 2 so tu nhien biet hieu chung = 84 UCLN = 12
3,tim 2 so tu nhien biet tich = 864 UCLN=6
4,cho 3n+1 va 5n+4 la 2 so nguyen to cung nhau tim UCLN cua 3n+1 va 5n+4
5,cho a=123456789;b=987654321 . Tim UCLN cua a va b
Tim a,b biet UCLN(a,b)=7 ,ab=588 va a<b
Tim 2 so tu nhien a,b biet tong cua chung bang 60 va UCLN (a,b) =12.
Tim hai so tu nhien a va b biet
a>b;a+b=108 va UCLN (a,b)=12
BCNN[a,b] = 240 va UCLN[a,b] = 12
giai giup minh nhe
bai 1 a )tim ucln(6n+3,6n+9)
b)tim ucln (2n-1;9n+4)
bai2 tim a;b thuoc n biet
bcnn(a;b)=240
ucln(a;b)=16
bai 3 tim so chia va thuong cua 1 phep chia biet so bi chia la 145 du 12 thuong # 1
tim so tu nhiên a va b biet ucln (a va ) = 4 va a + b = 48