Tìm x:
a) (X x 0,25 + 1999) x 2000 = ( 53 + 1999 ) x 2000
b) 71 + 65 x 4 = \(\dfrac{x+140}{x}\) + 260
Tìm x
71 + 65 x 4 = \(\frac{x+140}{x}+260\)
1.Tìm x biết:
71 + 65*4=x + 140 / x + 260
2.Tính
A = 6666666666 * 3333333333
71 + 65 x 4 = \(\frac{x+140}{x}+260\).Tìm x
Bài 3 : Tìm y ,x
a) 71 + 65 x 4 = \(\frac{X+140}{X}+260\)
b) y x 15/2 - 1/3 x ( 1/4 + y ) = \(96\frac{2}{3}\)
tìm X
71 + 65 x 4 = X + 140 / X +260
71 + 65 x 4 \(=\frac{x+140}{x}+260\)
Tìm \(x\)
\(71+65\)x 4= \(\frac{x+140}{x}\)+ 260
1 tìm x
a , ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10) + ..........+ ( x + 28 ) = 155
b, ( x x 0,25 + 1999 ) x 2000 = ( 53 + 1999 ) x 2000
c, 71 + 65 x 4 = \(\frac{x+140}{x}\)x 260