Question

tìm A=3 /5+ 6 và 5/6 [11 va 5/20-9 va 1/4] chia 8 va 1/3

Answer 1

\(A=\frac{3}{5}+6\frac{5}{6}.\left(11\frac{5}{20}-9\frac{1}{4}\right):8\frac{1}{3}\)

\(A=\frac{3}{5}+\frac{41}{6}.\left(\frac{23}{2}-\frac{37}{4}\right):\frac{25}{3}\)

\(A=\frac{3}{5}+\frac{41}{6}.\frac{9}{4}.\frac{3}{25}\)

\(A=\frac{3}{5}+\frac{41.9.3}{6.4.25}\)

\(A=\frac{3}{5}+\frac{41.3.3.3}{3.2.2.2.25}\)

\(A=\frac{3}{5}+\frac{41.9}{8.25}\)

\(A=\frac{3}{5}+\frac{369}{200}\)

\(A=\frac{489}{200}\)

Vậy \(A=\frac{489}{200}\)

Answer 2

5/6+6*5/6*(11*5/20-9*1/4)/8*1/3