ta có:
a/5=b/4
=> a^2/5^2=b^2/4^2=a^2-b^2/25-16=81/9=9
=> a^2=9*25
=> a=15 hoặc a=-15
b^2=16*9=144
=> b=12 hoặc b=-12
ta có:
a/5=b/4
=> a^2/5^2=b^2/4^2=a^2-b^2/25-16=81/9=9
=> a^2=9*25
=> a=15 hoặc a=-15
b^2=16*9=144
=> b=12 hoặc b=-12
Viet cac bieu dai so de dien dat cac y sau
a, tong cua a va b binh phuong
b, tong cac binh phuong cua avab
c, binh phuong cua tong ava b
{ cam on nhieu nheeeeee!!!! }
co tim duoc 2 so a va b de 2011ab la binh phuong cua 1 so tu nhien ko?
So A duoc chia thanh 3 so ti le theo 3/5 : 2/3 : 3/4. Biet rang tong cac binh phuong cua 3 so do bang 4921. Tim so A
bai 1 A=1+1^2+1^4+...+1^100
bai 2 tim mot so sao cho no nam giua x+5 va x-5 la binh phuong cua so do
k day nhanh len nha
cho p la phan so nguyen to lon hon 3
a) tim so du khi p binh phuong cho 3
b) hoi p binh phuong +2015 la so nguyen to hay hop so
Bai 4: Trong mot bai kiem tra toan, mot lop gom ba to A, B va C, diem trung binh cua hoc sinh o cac to duoc thong ke nhu sau: A: 9,0;
B: 8,8: C:7,8; A va B: 8,9: B va C:8,2. Biet to A co 10 hoc sinh, hay xac dinh so hoc sinh va diem trung binh toan lop
so a duoc chia thanh 3 so ti le theo 2/5;3/4;1/6. Biet rang tong binh phuong cua ba so do bang 24309. Tim so a
cho f(x) = ax3 + bx2+c+d (a,b,c,d thuoc z) va thoa man b= 3ac
cmr: f(1) , f(-2) la binh phuong mot so nguyen
cho A duoc chia thanh 3 so theo ti le 2/5;3/4;1/6.Biet rang tong cac binh phuong cua 3 so do la 24309.Tim so A