[246/369 + 1616/2121] = 5/21 nhân a
hay tìm a
Tìm A , biết : [ 246/369 + 1616/2121] = 5/21 x A
tìm y biết
242/363 + 1616/ 2121= 5/7 x y
\(\left(\frac{242}{363}+\frac{1616}{2121}\right)=\frac{2}{7}\cdot\frac{2015}{A}\)Tìm A biết:
242/363 + 1616/2121 = 2/7 nhân y
Tìm M biết : (242/363 + 1616/2121) = 2/7 x M
Bài 2:Tìm y
a) 242/363 + 1616/2121 = 2/7 x y
b) (y + 1/4) + (y + 1/16) + (y + 1/16) =2
cứu vs=)
(242/363+1616/2121)=2/7*x
( 242/362+ 1616/2121) = 2/7 * m