2 . \(\left(\frac{2}{5}.a+0,2.a\right)\) - 1,5 = \(\frac{5}{2}\)
2.\(\left[a.\left(\frac{2}{5}+0,2\right)\right]-1,5=\frac{5}{2}\)
2. a. 0,6 - 1,5 = 2,5
2a.0,6 = 1
2a = \(\frac{5}{3}\)
a = \(\frac{5}{6}\)
2 . \(\left(\frac{2}{5}.a+0,2.a\right)\) - 1,5 = \(\frac{5}{2}\)
2.\(\left[a.\left(\frac{2}{5}+0,2\right)\right]-1,5=\frac{5}{2}\)
2. a. 0,6 - 1,5 = 2,5
2a.0,6 = 1
2a = \(\frac{5}{3}\)
a = \(\frac{5}{6}\)
Bài 1 : Tìm x
a, \(\frac{1}{2}+x+1\frac{1}{2}=3\frac{3}{4}\)
b, \(\frac{5}{6}\div x-\frac{4}{9}=\frac{3}{4}\)
Tìm a
a) 24+3x(5xa)=27
b) (1,5 - a ):\(\frac{3}{4}=\frac{20}{9}\)
c) a x \(2\frac{1}{5}-\)a x\(\frac{4}{7}=\frac{5}{77}\)
d) {37 -2 x (a - 3,25)} : 5 = 7,06
bài 2:tìm x phân số
a)\(x:\frac{5}{4}=\frac{9}{5}+\frac{1}{2}=?\) b)\(\left(x+\frac{3}{4}\right)x\frac{5}{7}=?\frac{10}{9}\)
Bài 1:Tìm x,biết:
a)(1,5*1,9-x-0,5):0,25=7,5:0,125
b)1-\(\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\):2\(\frac{1}{6}\)=0
c)35*\(\left(2\frac{1}{5}-x\right)\)=32
d)\(\frac{4}{3}\)+\(\left(x:2\frac{2}{3}-0,5\right)\)*1\(\frac{35}{55}\)=0,6
e)1\(\frac{1}{3}\)*2\(\frac{2}{4}:\frac{5}{6}\)*1\(\frac{1}{11}\)=11-5:x
Mình cần gấp lắm!Ai nhanh nhất mik tik nha!
\(A=\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)\(B=\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{4}\right)x.......x\left(1-\frac{1}{2015}\right)x\left(1-\frac{1}{2016}\right)\)
\(C=5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2x2\frac{1}{3}\right):\frac{7}{4}\)
Tìm x biết
a) \(x+\frac{1}{5}-\frac{27}{10}=4\frac{1}{2}\)
b) \(1\frac{3}{4}+x-\frac{7}{8}=5\)
c) 5,15 < 5,x8 < 5,68
Tìm X biết
a) \(x\cdot\frac{2}{7}\cdot\frac{3}{4}=\frac{5}{21}\)
b) \(x\cdot\frac{1}{2}=\frac{1}{3}\)
c) \(x:\frac{4}{5}=\frac{25}{8}:\frac{5}{4}\)
tìm x:
a) \(x-\frac{5}{7}-\frac{13}{14}=1\) b) \(\frac{3}{5}+x+1\frac{1}{5}=\frac{11}{3}\) c) \(x.\frac{4}{5}:2=\frac{6}{7}\) d) \(\frac{6}{5}:x:\frac{5}{4}=\frac{10}{15}\)
Tìm x biết:
a, \(\frac{x:3-16}{2}\)+21=38
b, \(\frac{1}{4}+\frac{1}{3}:\frac{1}{x}=\frac{11}{12}\)
c, 4+\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\)\(\frac{2}{xXx\left(x+1\right)}\)