Question

Tìm a, b, c. Biết:

\(\frac{a}{3}=\frac{b}{5};\frac{b}{6}=\frac{c}{4}\) và a + b - c = -56

Answer 1

\(\frac{a}{3}=\frac{b}{5}\Leftrightarrow\frac{a}{18}=\frac{b}{30}\left(1\right)\)

\(\frac{b}{6}=\frac{c}{4}\Leftrightarrow\frac{b}{30}=\frac{c}{20}\left(2\right)\)

\(Từ\left(1\right);\left(2\right)\Rightarrow\frac{a}{18}=\frac{b}{30}=\frac{c}{20}=\frac{a+b-c}{18+30-20}=\frac{-56}{28}=-2\)

=>a/18=-2 vậy a= -36

=>b/30=-2 vậy b=-60

=>c/20=-2 vậy c = -40

Answer 2

ta co 

\(\frac{a}{3}=\frac{b}{5}\)\(=\frac{a}{3\cdot6}=\frac{b}{5\cdot6}=\frac{a}{18}=\frac{b}{30}\left(1\right)\)

\(\frac{b}{6}=\frac{c}{4}=\frac{b}{6\cdot5}=\frac{c}{4\cdot5}=\frac{b}{30}=\frac{c}{20}\left(2\right)\)

tu 1va 2 suy ra

\(\frac{a}{18}=\frac{b}{30}=\frac{c}{20}\)

ap dung tinh chat day ti so bang nhau ta duoc

\(\frac{a}{18}=\frac{b}{30}=\frac{c}{20}=\frac{a+b-c}{18+30-20}=\frac{-56}{28}=-2\)

tu \(\frac{a}{18}=-2\Rightarrow a=-2\cdot18=-36\)

\(\frac{b}{30}=-2\Rightarrow b=-2\cdot30=-60\)

\(\frac{c}{18}=-2\Rightarrow c=-2\cdot20=-40\)

Vậy a=-36; b=-60; c=-40

k nha

thanks