x/2=y/3=>x/8=y/12
y/4=z/5=>y/12=z/15
=>x/8=y/12=z/15=(x+y-z)/(8+12-15)=10/5=2(áp dụng tính chất dãy tỉ số = nhau;x+y-z=10)
=>x/8=2=>x=16
y/12=2=>y=24
z/15=2=>z=30
\(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{12}\)
\(\frac{y}{4}=\frac{z}{5}\Rightarrow\frac{y}{12}=\frac{z}{15}\)
\(\Rightarrow\frac{x}{8}=\frac{y}{12}=\frac{z}{15}=\frac{x+y-x}{8+12-15}=2\)
Ta có \(\frac{x}{8}=2\Rightarrow x=16\)
\(\frac{y}{12}=2\Rightarrow y=24\)
\(\frac{z}{15}=2\Rightarrow z=30\)
Vậy x=16; y=24; z=30