Ta có : \(\frac{a}{3}=\frac{b}{2}=\frac{c}{5};a-b+c=-20,4\)
Áp dụng tính chất của dãy tỉ số bằng nhau , ta có :
\(\frac{a}{3}=\frac{b}{2}=\frac{c}{5}=\frac{a-b+c}{3-2+5}=\frac{-20,4}{6}=-\frac{17}{5}\)
\(\Rightarrow\frac{a}{3}=-\frac{17}{5}\Rightarrow a=-\frac{51}{5}\)
\(\Rightarrow\frac{b}{2}=-\frac{17}{5}\Rightarrow b=-\frac{34}{5}\)
\(\Rightarrow\frac{c}{5}=-\frac{17}{5}\Rightarrow c=-17\)
\(\frac{a}{3}=\frac{b}{2}=\frac{c}{5}=\frac{a-b+c}{3-2+5}=\frac{-20}{6}=-\frac{10}{3}\)
\(\frac{a}{3}=\frac{-10}{3}=>a=-10\)
\(\frac{b}{2}=\frac{-10}{3}=>b=\frac{-20}{3}\)
\(\frac{c}{5}=\frac{-10}{3}=>c=\frac{-50}{3}\)