Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
tim hai so a va b biet a.b=2250va UCLN(a,b)=15
tin 2 so a va b biet rang a.b=1176;BCNN(a,b)=84 va a>b
a, ab = 360 va BCNN[ a;b] = 60
b, UCLN[a:;b] =12 va BCNN[a;b] = 72
c, UCLN[a;b] = 15 va BCNN[a;b]=2100.UCLN[a;b]
tim 2 so tu nhien a,b (a<b) biet : BCNN(a,b) =120 va UCLN(a,b)=19
tim 2 so tu nhien a va b biet rang BCNN;UCLN bang 15
Tim 2 so tu nhien a va b biet :
BCNN ( a , b) = 300 ; UCLN (a , b) = 15
giai giup minh nhe
bai 1 a )tim ucln(6n+3,6n+9)
b)tim ucln (2n-1;9n+4)
bai2 tim a;b thuoc n biet
bcnn(a;b)=240
ucln(a;b)=16
bai 3 tim so chia va thuong cua 1 phep chia biet so bi chia la 145 du 12 thuong # 1
tim hai so tu nhien a,b biet
BCNN(a,b)=192 va UCLN(a,b)=16
biet rang BCNN(a,b).UCLN(a,b)=a.b
a, tong cua hai so bang 60,tong giua UCLN va BCNN cua chung la 84 tim hai so do