B = 31 x 32 x 33 x......... x 90
= \(\frac{1x2x3x4x5..........90}{1x2x3x4...........30}\)
= (1 x 4 x 7 x.......... x 88) x (2 x 5 x 8 x ....... x 89) x \(\frac{3x6x9x........x90}{1x2x3x..........x30}\)
= (1 x 4 x 7 x ........ x 88) x (2 x 5 x 8 x .........89) x 3030
Vậy có 30 thừa số 3