Question

thực hien phep tinh

x + 2 trên x cộng 2x-1 trên 2 - x trừ x - 8 trên x² - 2x

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Answer 1

\(\frac{x+2}{x}+\frac{2x-1}{2-x}-\frac{x-8}{x^2-2x}\)

\(=\frac{x+2}{x}-\frac{2x-1}{x-2}-\frac{x-8}{x\left(x-2\right)}\)

\(=\frac{\left(x-2\right)^2}{x\left(x-2\right)}-\frac{x\left(2x-1\right)}{x\left(x-2\right)}-\frac{x-8}{x\left(x-2\right)}\)

\(=\frac{x^2-4x+4-2x^2+x-x+8}{x\left(x-2\right)}=\frac{-x^2-4x+12}{x\left(x-2\right)}\)

\(=\frac{\left(x+6\right)\left(x-2\right)}{x\left(x-2\right)}=\frac{x+6}{x}\)