\(\frac{1}{100.99}-\left(\frac{1}{99.98}+\frac{1}{98.97}+...+\frac{1}{2.1}\right)\)
\(=\frac{1}{100}-\frac{1}{99}-\left(\frac{1}{99}-\frac{1}{98}+\frac{1}{98}-\frac{1}{97}+...+\frac{1}{2}-1\right)\)
\(=\frac{1}{100}-\frac{1}{99}-\left(\frac{1}{99}-1\right)\)
\(=\frac{1}{100}-\frac{1}{99}-\frac{1}{99}+1\)
\(=\frac{9799}{9900}\)
Tính :
\(A=\frac{1\cdot98+2\cdot97+3\cdot96+......+98\cdot1}{1\cdot2+2\cdot3+3\cdot4+......+98\cdot99}\)
\(B=\frac{100-\left(1+\frac{1}{2}+\frac{1}{3}+..........+\frac{1}{100}\right)}{\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+.........+\frac{99}{100}}\)
Tính nhanh:
C=\(\frac{1}{100}-\frac{1}{100\cdot99}-\frac{1}{99\cdot98}-\frac{1}{98\cdot97}-...-\frac{1}{3\cdot2}-\frac{1}{2\cdot1}\)
Giúp mình nhé mình đang cần gấp
\(\frac{1\cdot98+2\cdot97+3\cdot96+...+96\cdot3+97\cdot2+98\cdot1}{1\cdot2+2\cdot3+3\cdot4+...+96\cdot97+97\cdot98+98\cdot99}\)
tính
\(\frac{1}{100\cdot99}\)-\(\frac{1}{99\cdot98}-\frac{1}{98\cdot97}-...-\frac{1}{3\cdot2}-\frac{1}{2\cdot1}\)
\(\frac{1}{100\cdot99}-\frac{1}{99\cdot98}-...-\frac{1}{3\cdot2}-\frac{1}{2\cdot1}\)
tính:\(\frac{1\cdot98+2\cdot97+3\cdot96+...+97\cdot2+98\cdot1}{1\cdot2+2\cdot3+3\cdot4+...+99\cdot100}\)
tính
\(\frac{1\cdot98+2\cdot97+3\cdot96+...+96\cdot3+97\cdot2+98\cdot1}{1\cdot2+2\cdot3+3\cdot4+...+96\cdot97+97\cdot98+98\cdot99}\)
ai đó giúp mk mha mk sẽ tick cho người giúp mk làm ra đầu tiên
Tính:
D = \(\frac{1+\left(1+2\right)-\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1\cdot98+2\cdot97+3\cdot96+...+98\cdot1}\)
\(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1\cdot99}+\frac{1}{3\cdot97}+\frac{1}{5\cdot99}+...+\frac{1}{97\cdot3}+\frac{1}{99\cdot1}}\)
