Bài 1:
a) - | 12 - 14 | - | 98 - 15 + 2 | - 14
= - | - 2 | - | 85 | - 14
= -2 - 85 - 14
= -101
b) ( -24 ) - ( 12 - 19 ) - | 15 - 12 - 7 |
= ( -24 ) - ( - 7 ) - | -4 |
= ( -24 ) + 7 - 4
= -21
Bài 2:
a) 5 - ( 1997 - 2005 ) + 1997
= 5 - 1997 + 2005 + 1997
= ( 5 + 2005 ) + ( 1997 - 1997 )
= 2010 + 0
= 2010
b) 1579 - ( 53 + 1679 ) - ( -53 )
= 1579 - 53 - 1679 + 53
= ( 1579 - 1679 ) + ( 53 - 53 )
= ( -100 ) + 0
= -100
c) -48725 - ( 357 - 48725 ) + 300
= -48725 - 357 + 48725 + 300
= [( -48725 ) + 48725 ] + ( 357 - 300 )
= 0 + ( -57 )
= -57
d) 4567 + ( 1234 - 4567 ) - 4
= 4567 + 1234 - 4567 - 4
= ( 4567 - 4567 ) + ( 1234 - 4 )
= 0 + 1230
= 1230
a) \(-\left|12-14\right|-\left|98-15+2\right|-14\)
\(=-\left|2\right|-\left|85\right|-14\)
\(=\left(-2\right)-85-14\)
\(=\left(-2\right)-\left(85+14\right)\)
\(=\left(-2\right)-99\)
\(=\left(-2\right)+\left(-99\right)=-101\)
2)
a) \(5-\left(1997-2005\right)+1997\)
\(=5-1997+2005+1997\)
\(=5+2005+\left(1997-1997\right)\)
Do một bên trừ một bên cộng đấy :)
\(=2010\)
b) \(1579-\left(53+1679\right)-\left(-53\right)\)
\(=1579-53-1679+53\)
\(=\left(-1679\right)-\left(1579\right)\)
