\(\dfrac{x+1}{3\left(x-2\right)}:\dfrac{x}{3\left(x^2-4x+4\right)}=\dfrac{x+1}{3\left(x-2\right)}:\dfrac{x}{3\left(x-2\right)^2}=\dfrac{x+1}{3\left(x-2\right)}.\dfrac{3\left(x-2\right)^2}{x}=\dfrac{\left(x+1\right)3\left(x-2\right)^2}{3x\left(x-2\right)}=\dfrac{\left(x+1\right)\left(x-2\right)}{x}\)