a,thay x=3
A=\(\left(3-2\right)\left(3^4+2.3^3+4.3^2+8.3+16\right)=211\)
b. thay x=2
\(B=\left(2+1\right)\left(2^6-2^5+2^4-2^3+2^3-2+1\right)=129\)
c, thay x=2;y=\(-\frac{1}{2}\)
\(C=\left(2^3-2^2.\frac{-1}{2}+2.\frac{-1}{2}^2-\frac{-1}{2}^3\right)\left(2+\frac{-1}{2}\right)=\frac{255}{16}\)