#)Giải :
a)\(9^2\div\left(27^3.81^2\right)=9^2\div\left[\left(3^3\right)^3.\left(9^2\right)^2\right]=9^2\div\left(3^9.9^4\right)\)
Tự lm típ
a,\(9^2:\left(27^3.81^2\right)=3^4:\left(3^9.3^8\right)=3^4:\left(3^{9+8}\right)=3^4:3^{17}=3^{-13}\)
\(a,\frac{9^2}{27^3.81^3}=\frac{3^4}{3^9.3^{12}}=\frac{1}{3^{17}}\)
\(b,\frac{2.8^4.27^2+4.6^9}{2^{12}.9^3.31}=\frac{2^{13}.3^6+2^22^9.3^9}{2^{12}.3^6.31}\)
\(=\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{12}.3^6}=\frac{4+27}{2}=\frac{31}{2}\)