Question

Thực hiện phép chia:

               [7(x-y)⁵+6(y-x)⁴-2(x-y)³+(y-x)² ]:(x-y)²

Answer 1

Có:

\(\left[7\left(x-y\right)^5+6\left(y-x\right)^4-2\left(x-y\right)^3+\left(y-x\right)^2\right]:\left(x-y\right)^2\)

\(=\left[7\left(x-y\right)^5+6\left(x-y\right)^4-2\left(x-y\right)^3+\left(x-y\right)^2\right]:\left(x-y\right)^2\)

\(=\left[7\left(x-y\right)^5:\left(x-y\right)^2\right]+\left[6\left(x-y\right)^4:\left(x-y\right)^2\right]-\left[2\left(x-y\right)^3:\left(x-y\right)^2\right]+\left(x-y\right)^2:\left(x-y\right)^2\)

\(=7\left(x-y\right)^3+6\left(x-y\right)^2-2\left(x-y\right)+1\)